Question 1191118
i think this works like t his:


s(1) = 5
s(n) = s(n-1) + 5 for n >= 2


if n = 2, then:
s(2) = s(2-1) + 5 = s(1) + 5 = 5 + 5 = 10


if n = 3, then:
s(3) = s(3-1) + 5 = s(2) + 5 = 10 + 5 = 15


etc.