Question 1191100
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  a\sum_{i=0}^n\ 2^i\ =\ a\(2^{n+1}\ -\ 1\)]


Where *[tex \Large a] is the first amount.


Calculate for *[tex \Large n\ =\ 20]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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