Question 1191084
10 independent trials
constant probability of success of 0.7 for each
exactly 5 is 10C5*0.7^5*0.3^5=0.1029=0.103
at least one business is 1- p(0) businesses.
p(0)=0.3^10=0.0000059
so the probability that at least one has a web site is 1.0, rounded from 0.999994