Question 1191085
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A local county has an unemployment rate of 4.7%. A random sample of 17 employable people 
are picked at random from the county and are asked if they are employed. 
Find the probability that exactly 5 in the sample are unemployed. 
(The distribution is a binomial. Round your answers to 4 decimal places.)
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<pre>
It is the binomial type probability distribution.


The number of trials n= 17; the probability of a success individual trial is  0.047,  and the number of success trials k = 5. 


    P = {{{C[17]^5*0.047^5*(1-0.047)^(17-5)}}} = {{{((17*16*15*14*13)/(1*2*3*4*5))*0.047^5*0.953^12}}} = 0.0007964   (rounded).     <U>ANSWER</U>
</pre>

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To see many other similar &nbsp;(and different) &nbsp;solved problems, &nbsp;look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-manually.lesson>Simple and simplest probability problems on Binomial distribution</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Typical-binomial-distribution-probability-problems.lesson>Typical binomial distribution probability problems</A> 

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