Question 1191013

the equation of the line with a slope of {{{m=-2/3}}} that passes through the point ({{{-1}}},{{{7}}})

use point slope formula

{{{y-y[1]=m(x-x[1])}}} ..........substitute given

{{{y-7=-(2/3)(x-(-1))}}} 

{{{y=-(2/3)(x+1)+7}}} 

{{{y=-(2/3)x-(2/3)(1)+7}}} 

{{{y=-(2/3)x+19/3}}} 


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(-1,7,.12), locate(-1,7,p(-1,7)),
graph( 600, 600, -10, 10, -10, 10, -(2/3)x+19/3)) }}}