Question 112934
Looking at the sequence of the numerators, we see: 1,2,3,4,...



And we can see that the numerators are increasing by 1 each time and start at 1. So if we start at n=0, then the general sequence for the numerators is: {{{n+1}}}



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Looking at the sequence of the denominators, we see: 3,4,5,6,...



And we can see that the denominators are increasing by 1 each time, but are starting at 3. So if we start at n=0, then the general sequence for the denominators is: {{{n+3}}}



So putting this all together we get


{{{(n+1)/(n+3)}}}



Notice if we let n=0, we get


{{{(0+1)/(0+3)=1/3}}}


If we let n=1, we get


{{{(1+1)/(1+3)=2/4}}}



If we let n=2, we get


{{{(2+1)/(2+3)=3/5}}}



And finally, if we let n=3, we get


{{{(3+1)/(3+3)=4/6}}}



So this verifies our answer.