Question 1190872
y=0, then x=-4/(x-5)
x^2-5x=-4 multiplying through
x^2-5x+4=0
(x-4)(x-1)=0
x=4 and 1, so looking at (1, 0) and (4, 0)
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take the derivative:
y'=1-4/(x-5)^2
=1-[4/(x-5)^2]. When x=1 y'=1-(1/4) so slope is (3/4);when x=4 y'=-3


{{{graph(300,300,-5,5,-5,5,x+(4/(x-5)))}}}