Question 1190910
f(x)=8-x^3
inverse
x=8-y^3
y^3=8-x
y=(8-x)^(1/3)
{{{graph(300,300,0,10,-10,10,8-x^3,(8-x)^(1/3))}}}
To find the points for the inverse, (8, 0) is one, and (0, 2) is the other.  The two are equal when 
8-x^3=(8-x)^(1/3)
One way is to graph both and find where they intersect, which is at x=1.834.
One can put in points for x and take the cube root.