Question 1190852
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the outside of a picture frame has a length which is 5cm more than the width, 
the area enclosed of the picture frame is 126cm 
what is the width of the outside


<pre>
    w*(w+5) = 126


    w^2 + 5w - 126 = 0


    {{{w[1,2]}}} = {{{(-5 +- sqrt(5^2 -4*1*(-126)))/2}}} = {{{(-5 +- sqrt(529))/2}}} = {{{(-5+- 23)/2}}}.


We discard the negative root and accept the positive one.


<U>ANSWER</U>.  The width is  {{{(-5 + 23)/2}}} = 9 cm.
</pre>

Solved.