Question 1190846


{{{S=(wd)/h(h-d/2)}}}...... make {{{h}}} the subject


{{{S(h(h-d/2))=(wd)}}}


{{{h(h-d/2)=(wd)/S}}}


{{{h^2-(d/2)h=(wd)/S}}}........complete square on left side


{{{(h^2-(d/2)h+b^2)-b^2=(wd)/S}}}........{{{b=(d/2)/2=d/4}}}


{{{(h^2-(d/2)h+(d/4)^2)-(d/4)^2=(wd)/S}}}


{{{(h-d/4)^2-d^2/16=(wd)/S}}}


{{{(h-d/4)^2=(wd)/S+d^2/16}}}


{{{h-d/4=sqrt((wd)/S+d^2/16)}}}


{{{h=sqrt((wd)/S+d^2/16)+d/4}}}