Question 112856
Given:
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{{{7p+6q)^2}}}
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To expand this recognize that when you square a quantity you multiply it by itself. 
Therefore, multiply {{{(7p+6q)}}} by itself. You can write this problem as:
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{{{(7p+6q)*(7p+6q)}}}
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To do this multiplication, you can first multiply the {{{7p}}} in the first set of parentheses
by each of the terms in the second set of parentheses. In other words, multiply:
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{{{7p*(7p + 6q)}}} and you get {{{49p^2 + 42pq}}}. 
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Next multiply the {{{6q}}} in the first set of parentheses by each of the terms in the second
set of parentheses. In other words, this time multiply:
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{{{6q*(7p + 6q)}}} and you get {{{42pq + 36q^2}}}
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Finally, add the two products and simplify. Adding the two products:
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{{{49p^2 + 42pq + 42pq + 36q^2}}}
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Notice that the two middle terms can be combined, and the resulting polynomial is:
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{{{49p^2 + 84pq +36q^2}}}
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That's the answer to the problem. Hope this helps you to understand how to square a binomial
quantity.
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