Question 1190827
<br>
Let the number be x; then twice the reciprocal is 2/x.<br>
The sum of the two s 51/5:<br>
{{{x+2/x=51/5}}}<br>
Multiply everything by the least common denominator 5x to clear fractions:<br>
{{{5x^2+10=51x}}}
{{{5x^2-51x+10=0}}}
{{{(5x-1)(x-10)=0}}}
{{{x=1/5}}} or {{{x=10}}}<br>
ANSWER: The two numbers are 1/5 and 10<br>
CHECK:
x=1/5 --> 2/x=10 --> x+2/x=10+1/5=51/5
x=10 --> 2/x=1/5 --> x+2/x=10+1/5=51/5<br>