Question 1190726
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Over a period of three months during one​ year, an​ airline's rate of involuntarily 
denying boarding was 0.85 per​ 10,000 passengers.
What is the probability that in the next​ 10,000 passengers, 
there will be no one involuntarily denied​ boarding?
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            Assume that the rate remains the same in the next  10,000  passengers.



<pre>
The probability that a passenger will involuntary denyed boarding is  P = {{{0.85/10000}}} = 0.000085.


The probability that a passenger will not involuntary denyed boarding is the complement

      P' = 1 - 0.000085 = 0.999915.


The probability that in the next​ 10,000 passengers, there will be no one involuntarily denied​ boarding is

      {{{0.999915^10000}}} = 0.427399491,  or   0.4274 = 42.74%  (rounded).      <U>ANSWER</U>
</pre>

Solved.