Question 1190609
<br>
Both responses you have received so far show valid solution methods.<br>
I personally would take some time figuring out how to set up the problem so that I use fractions as little as possible.<br>
(1) Paul had 2/3 as much as Simon:
Paul = 2x; Simon = 3x<br>
(2) 1/3 of Peter's money was $15 more than 1/4 of Paul's money:
I need an expression for 1/4 of Paul's money, which I currently have defined as 2x.  I'll change that to 4x to make 1/4 of Paul's money a whole number times my variable x:
Paul = 4x; Simon = 6x<br>
Now 1/3 of Peter's money is $15 more than 1/4 of 4x, which is x:
1/3 of Peter's money = x+15
Peter's money: 3x+45<br>
Now we have "nice" expressions for each person's money:
Paul = 4x; Simon = 6x; Peter = 3x+45<br>
The total is $825:
4x+6x+3x+45=825
13x=780
x=60<br>
Paul: 4x=240
Simon: 6x=360
Peter: 3x+45=225<br>
ANSWER: (how much more money Simon had the Peter): $360-$225=$135<br>