Question 112835
{{{log(x, (4)) + log(x, (9))  = 2}}} Start with the given equation



{{{log(x, (4*9)) = 2}}} Combine the logarithms using the identity {{{log(b, (x)) + log(b, (y))=log(b,(x*y))}}}



{{{log(x, (36)) = 2}}} Multiply



{{{x^2=36}}} Rewrite the logarithm in exponent form. In other words, use: {{{log(b,(x))=y}}}===> {{{b^y=x}}}




{{{sqrt(x^2)=sqrt(36)}}} Now take the square root of both sides



So our answer is 


{{{x=6}}}