Question 1190555
.
Calculate the gradient of the curve for y = x^2 - 2x at the point where y = -1.
~~~~~~~~~~~~~~~~


<pre>
They want you calculate the derivative and evaluate it at the point, where y= -1.


The derivative is  {{{(dy)/(dx)}}} = 2x - 2.     (1)


The point where y= -1 is  

    -1 = x^2 - 2x

    x^2 - 2x + 1 = 0

    (x-1)^2 = 0

     x = 1.


So, we substitute x= 1 into the expression for the derivative (1), and we get the gradient

    gradient = 2*1 - 2 = 0.    <U>ANSWER</U>


<U>ANSWER</U>.  The gradient is zero at the point where y = -1.
</pre>

Solved.