Question 1190550
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The terms are {{{4x^2}}}, {{{9xy}}}, {{{-8x}}}, and {{{-18y}}}<br>
(1) Pick any two terms that have a common factor and make them a group; make the remaining two terms a second group.  The first two terms have an x in common, so we can group them.  The expressions is then<br>
{{{(4x^2+9xy)+(-8x-18y)}}}<br>
Factor the common factor out of the first group of two terms, and factor any common factor out of the other group of two terms:<br>
{{{x(4x+9y)+(-2(4x+9y))}}}<br>
The binomial factors from both groups are the same, so the expression can be factored by grouping:<br>
{{{4x^2+9xy-8x-18y=x(4x+9y)-2(4x+9y)=(x-2)(4x+9y)}}}<br>
Note we can reach the same result by grouping the first and third terms, which have a 4x in common:<br>
{{{4x^2+9xy-8x-18y=(4x^2-8x)+(9xy-18y)=4x(x-2)+9y(x-2)=(4x+9y)(x-2)}}}<br>