Question 1190279


 Solve {{{3cos(x+40) = 4sin(x+40)}}} for {{{0}}}° ≤ {{{x}}} ≤ {{{360}}}°


{{{3cos(x+40) = 4sin(x+40)}}} 


{{{3/4= sin(x+40) /cos(x+40) }}}


{{{tan(x+40) =3/4}}}


{{{x+40=tan^-1(3/4)}}}


{{{x  =  tan^-1(3/4)-40}}}° 


solutions: 


{{{x=tan^-1(3/4)+180*n-40}}}° 


for range {{{0}}}° ≤ {{{x}}} ≤ {{{360}}}°


radians:

{{{x = (16pi)/9 + 2tan^(-1)(1/3)}}}

{{{x = (16pi)/9 - 2tan^(-1)(1/3)}}}


degrees:

{{{x=356.87}}}° 

{{{x=283.13}}}°