Question 1190280


 Find all the angles of {{{x}}} for {{{0 < x < 360}}}° which satisfy {{{cot(2x+10) = -0.5}}}


{{{cot(2x+10) = -0.5}}}

{{{2x+10 = cot^-1(-0.5)}}}

{{{x  =  cot^-1(-0.5)-10}}}° 


solutions: 


{{{x = (17pi)/36 - (1/2) cot^(-1)(1/2)}}}

{{{x = (35pi)/36 - (1/2) cot^(-1)(1/2)}}}

{{{x = (53pi)/36 - 1/2 cot^(-1)(1/2)}}}

{{{x = (71pi)/36 - (1/2) cot^(-1)(1/2)}}}


degrees:

{{{x=116.72}}}° 
 
{{{x=143.28}}}°  

{{{x=233.28}}}° 

{{{x=323.28}}}°