Question 1190383
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tan(angle) = opposite/adjacent
tan(angle) = 5/8
tan(angle) = 0.625
angle = arctan(0.625) .... same as inverse tangent i.e. *[Tex \large \tan^{-1}]
angle = 32.00538


The angular height is roughly 32.00538 degrees above the horizontal
This is the angle of elevation.


Extra info:
An angular height of 0 degrees means the sun is at the horizon (sunrise or sunset)
An angular height of 90 degrees means it is 12:00 PM noon.
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