Question 1190319
x, short leg
x+4, long leg
x+8, hypotenuse


{{{x^2+(x+4)^2=(x+8)^2}}}
.
.
.
{{{x^2-8x-48=0}}}
{{{(x-12)(x-4)=0}}}


12, short leg
16, long leg
20, hypotenuse