Question 1190283

 Find the values of {{{x}}}, where {{{0 < x <180}}}° such that {{{sin(3x+70) = 0.2}}}


{{{ sin(3x+70) = 0.2}}}

{{{3x+70 =  sin^-1(0.2)}}}


solve {{{3x+70° =180-  sin^-1(0.2)+360*n}}}


{{{x=360*n/3+sin^-1(0.2)/3-23.33333}}}° 

{{{x=60-23.33333+360*n/3-sin^-1(0.2)/3}}}°



Solutions for the range {{{0<x<180}}}°:


Radians:
{{{x=0.57283}}}
{{{x=1.75427}}}
{{{x=2.66722}}}


Degrees:

{{{x=32.8207}}}° 
{{{x=100.51}}}°  
{{{x=152.82}}}°