Question 1190239
 Jordan has pennies, nickels, dimes, and quarters.
p = no. of pennies
n = nickels
d = dimes
q = quarters
write an equation for each statement
 He has a total of $14.18.
.01p + .05n + .10d + .25q = 14.18
get rid of all these decimals, mult by 100
p + 5n + 10d + 25q + 1418
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we will try to get all variables in terms q
 He has one more quarters than pennies
q = p + 1
p = q - 1
 and three fewer dimes than nickels.
d = n - 3
 He also has ten more quarters than nickels
q = n + 10
n = q - 10
 and thirteen more quarters than dimes.
q = d + 13
d = q - 13
in the first equation (simplified),replace as follows
(q-1)+5(q-10)+10(q-13)+25q = 1418
q + 1 + 5q - 50 + 10q - 130 + 25q = 1418
q + 5q + 10q + 25q - 1 - 50 - 130 = 1418
41q - 181 = 1418
41q = 1418 + 181
41q = 1599
q = 1599/41
q = 39 quarters
then
p = 39 - 1 = 38 pennies
n = 39 - 10 = 29 nickels
d = 39 - 13 = 26 dimes
:
See if this checks out
.01(38) + .05(29) + .10(26) + .25(39) = 
.38 + 1.45 + 2.60 + 9.75 = $14.18


 
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