Question 1190235
<font face="Times New Roman" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ kx^2]



Substitute 98 for *[tex \Large y] and 7 for *[tex \Large x] and then solve for *[tex \Large k].  Then, using this value for *[tex \Large k] solve for *[tex \Large y] when *[tex \Large x\ =\ 5]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>