Question 1190224
<font color=black size=3>
The given equation is in the form {{{ax^2+bx+c=0}}}
We have
a = 5
b = -11
c = -124


They are plugged into the quadratic formula below


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-11)+-sqrt((-11)^2-4(5)(-124)))/(2(5))}}}


{{{x = (11+-sqrt(2601))/(10)}}}


{{{x = (11+sqrt(2601))/(10)}}} or {{{x = (11-sqrt(2601))/(10)}}}


{{{x = (11+51)/(10)}}} or {{{x = (11-51)/(10)}}}


{{{x = (62)/(10)}}} or  {{{x = (-40)/(10)}}}


{{{x = 31/5}}} or  {{{x = -4}}}


{{{x = 6.2}}} or  {{{x = -4}}}


If you were to plot {{{y = 5x^2-11x-124}}} (you can use a free tool like GeoGebra or Desmos), then you should find the two x intercepts are exactly 6.2 and -4.


WolframAlpha is another useful tool to check your work. There are many many other free options out there as well.
</font>