Question 1190206
.


            A short version explanation


<pre>
You are given

    n = 9m + 6


(integer number n gives a remainder 6 when divided by 9).


Multiply both sides by 6. You will get

    6n = 6*9*m + 36.


It can be re-written equivalently as

    6n = = 9*(6m + 4),


which illustrates and proves that the number 6n is multiple of 9, i.e. is divisible by 9 with no remainder.
</pre>