Question 1190200
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0\ <\ a\ <\ 1]


means that *[tex \Large a] is positive.  Multiplying an inequality by a positive number retains the original sense of the inequality. So multiply by *[tex \Large a]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0\cdot a\ <\ a\cdot a\ <\ 1\cdot a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0\ <\ a^2\ <\ a]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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