Question 1189888
p hat mss 930/1500=0.62
99%CI half-interval is z(0.995)*sqrt (p*(1-p)/n)=2.576*sqrt (0.62*0.38/1500)=0.0323 or 3.2%
interval is (58.8%, 65.2%)
We are highly confident that the true proportion of US adults of voting age who vote lies in this interval.
If we ran 100 different samples and intervals, 95% of intervals would be expected to contain the true value.