Question 1190174

In factoring using the difference of cubes formula, if you have the problem 1+8x^3 do you need to switch it to 8x^3+1 to work or can you solve it the way it is written?
<pre>Given in that form (variable, preceded by the constant), it should be left as is. If it's a multiple-choice question, the 
answer would most likely be in that form also. Plus, you apply the same concept to get your answer. Below you'll find both forms: {{{matrix(1,5, 1 + 8x^3, "=", (1)^3 + (2x)^3, "===>", (1 + 2x)(1 - 2x + 4x^2))}}}
{{{matrix(1,5, 8x^3 + 1, "=", (2x)^3 + (1)^3, "===>", (2x + 1)(4x^2 - 2x + 1))}}}