<PRE><B>Question 1190150</B>
&lt;br&gt;
Using formal algebra....&lt;br&gt;
x = amount at 6%
17000-x = amount at 7%&lt;br&gt;
Total interest income $1150&lt;br&gt;
{{{.06(x)+.07(17000-x)=1150}}}&lt;br&gt;
Solve using basic algebra....  I leave that to you.&lt;br&gt;
If formal algebra is not required....&lt;br&gt;
(1) $17000 all invested at 6% would yield $1020 income; all at 7% would yield $1190 income; the actual income was $1150.
(2) Look at the three income amounts on a number line -- 1020, 1150, and 1190 -- and observe/calculate that $1150 is 130/170 = 13/17 of the way from $1020 to $1190.
(3) That means 13/17 of the total was invested at the higher rate.&lt;br&gt;
ANSWER: 13/17 of $17,000, or $13,000, at 7%; the other $4000 at 6%&lt;br&gt;
CHECK: .07(13000)+.06(4000)=910+240=1150&lt;br&gt;
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