Question 112726


{{{y=2x^2-(3x-5)}}}

{{{y=2x^2-3x+5}}}....to solve, set {{{y=0}}}

{{{0 =2x^2-3x+5}}}.........apply quadratic formula

{{{x[1,2]=(-b +- sqrt (b^2 -4*a*c )) / (2*a)}}}
{{{x[1,2]=(-(-3) +- sqrt ((-3)^2 -4*2*5 )) / (2*2)}}}
{{{x[1,2]=(3 +- sqrt (9 - 40 )) / 4}}}
{{{x[1,2]=(3 +- sqrt (- 31 )) / 4}}}
{{{x[1,2]=(3 +- sqrt ((-1) 31 )) / 4}}}
{{{x[1,2]=(3 +- 5.57i)/ 4}}}
{{{x[1]=(3 + 5.57i)/ 4}}}
{{{x[2]=(3 - 5.57i)/ 4}}}