Question 1190078
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Part A


You'll use a geometric probability distribution here. 


This is because we want to find the probability of the first success. 
More specifically, we want the probability when the first truck is overloaded (is it truck #1? truck #2? truck #3? etc)



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Part B


We use a binomial distribution here. 


Define "success" as "reaching the summit of Mount Kilimanjaro". Either a climber reaches the peak, or they don't. 
We have two outcomes per trial. Assume that the probability of success on any given trial is the same. Also, assume that no single climber affects any other climber (i.e. assume the trials to be independent). All of these conditions are needed to use the binomial distribution.


The binomial distribution will then allow us to make a table of X and P(X) values, where X is the number of successes (0,1,2,3,...). 
The list of all P(X) probabilities must add to 1, and each P(X) must be bound by the interval {{{0 <= P(X) <= 1}}}


Once the table is formed, you can then circle the row with the largest P(X) value to get an idea of the most likely outcome.
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