Question 1190062
Three consecutive even integers exist
n, (n+2), (n+4)
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 such that when the sum of the smallest and middle-valued integers is subtracted from the largest integer,
 the result is −18.
(n+4) - ((n+2) + n) = -18
remove the brackets, neg changes the signs
n + 4 - n - 2 - n = -18
combine like terms
n - n - n + 4 - 2 = -18
-n + 2 = -18
-n = -18 - 2
-n = -20
mult by -1, therefore
n = 20
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 What are the three integers? (Enter your answers as a comma-separated list.) 
20, 22, 24
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:
check: 
24 - (22 + 20)
24 - 42 = -18