Question 1190039


{{{2x+y <=2}}}

 to convert it to slope-intercept form, isolate {{{y}}}

{{{y <=-2x+2}}}

 
a table 

{{{x}}}|{{{y}}}
{{{-1}}}|{{{4}}}.....{{{y <=-2(-1)+2}}}->{{{y <=2+2}}}->{{{y <=4}}}
{{{0}}}|{{{2}}}....{{{y <=-2(0)+2}}}->{{{y <=0+2}}}->{{{y <=2}}}
{{{1}}}|{{{0}}}....{{{y <=-2(1)+2}}}->{{{y <=-2+2}}}->{{{y <=0}}}