Question 112706
If you look at the sum as it starts to accumulate, you'll notice a pattern.

.8
.88
.888
.8888
.88888
.888888
.8888888
.88888888

Look for a fraction that has a repeating pattern.
I know that 1/9=0.1111111....
So my sum looks like 8 times that much or 8/9. 
{{{sum( 8*10^(-n), 1, infinity )=8/9}}}