Question 1184165
(a) fraction of beads which was kept in container = 
1 - (1/3 + 4/9) = 1 - ((3 + 4)/9)
= 1 - 7/9
= (9 - 7)/9
= 2/9
fraction of beads kept in container = 2/9
(b) Let the total beads be x and y be the number of beads in short string
it is given that 1/3 of the beads are used in 7 long pieces of string and each long piece string had 15 more beads than each short string.
-> 1/(x) = 7(y + 15)
-> x = 21(y+15) - (1)

It is given that 4/9 of the beads are used in 16 short pieces of string.
-> 4/9x = 16y
-> x = 16 * 9/4y
-> x = 36y -(1)
from (1) and (2)
36y = 21(y + 15)
-> 36y = 21y + 315
-> 36 - 21y = 315
-> 15y = 315
-> y = 315/15 = 21
using this in (2) we have
x + 36 * 21 = 756
Total number of beads were 756