Question 1189911

(i)What is the charge for using 998 KWh in a month? 

C = 100 +1.75*998 

(ii)What is the charge for using 2500 KWh in a month? 

C= 100 +1000*1.75+(2500-1000) *3.52 

(iii) If C is the monthly charge for x KWh, develop a model relating the monthly charge and kilowatt-
hours used. That is, express C as a function of x.

C= 100 + 1000*1.75 +3.52(x-1000)