Question 1189913
a = number of advance tickets.
s = number of same day tickiets.


equations that need to be solved simultaneously are:
a + s = 55
30a + 40s = 1900


multiply both sides of the first equation by 30 and leave the second equatin as is to get:
30a + 30s = 1650
30a + 40s = 1900


subtract the first equation from the second to get:
10s = 250
solve for s to get:
s = 25
that makes a = 30 because a + s = 55


30a + 40s becomes 30 * 30 + 40 * 25 = 900 + 1000 = 1900
this confirms the values of a and s are correct.


the price of an advance ticket was 30 and the price of a same day ticket was 25.
that's your solution.