Question 1189872
The midpoint of AB has coordinate x which is the average of the two x components (-0.50) and the same for the two y components (4), so it is at (-0.5, 4).
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first day is sqrt(13) distance because distance is sqrt(difference x^2+difference y^2). That is to A.
Easier to do AB, and that distance is sqrt(5^2+4^2)=sqrt(41). Unlike slope, where which order you use the variable matters, it doesn't matter with distance, since you are squaring. You hike half of that the first day, so the total distance is sqrt(13)+(0.5)sqrt(41). That can be put into decimal form.
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The total distance is sqrt(13)+sqrt(41)+ the last leg, which is sqrt(40). The distance the second day is 
0.5*sqrt(41)+ sqrt (40)