Question 1189852
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After driving 30.0 km west, a car turns southwest and proceeds another 60.0 km. What is the displacement (in 
kilometers) of the car from the point of origin (magnitude only)? 

I tried to do {{{x=60sin45}}} so x=51.054 and {{{y=30+60cos45}}} so y=61.519 then to find the magnitude of displacement I used MagofDis= {{{sqrt(x^2+y^2)}}}
The answer I got was 6391.137567km but it does not look right.
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<pre>
You have a triangle with two sides of 30 km and 60 km and the angle of 135° between them.


You need to find the side length d opposite to this angle.


Use the cosine law

     d = {{{sqrt(30^2 + 60^2 - 2*30*60*(-sqrt(2)/2))}}} = 83.938 km  (rounded).    <U>ANSWER</U>
</pre>

Solved.