Question 112652
the first set of equation is: 


x + 2y = 7  and 3x + 5y = 17  


Multiply EQN(1) by 3 and subtract it from the second equation. We get: 


3x + 6y = 21 
3x + 5y = 17 
===========
y = 4 


Substituting in one of the equations we can find the value of x


x + 2(4)= 7 


==> x = 7 - 8 


==> x = -1 




The second set of equations are: 



x + 3y = 8 and 4x - 3y = 2


Adding the equations we get:



x + 3y = 8 
4x - 3y = 2 

=========== 
5x = 10


==> x = {{{10/5}}}


x = 2 


By back substitution we can find the value of y.



2 + 3y = 8 


3y = 8 - 2 


3y = 6  


y = {{{6/3}}}


y = 2 


thus the solution



NOTE: If these are not the set of equations then mail me back with the correct set of equations wil send you the answers as soon as possible. 


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