Question 112609
Mathematicians don't like sqrt's in the denominator. They try to find some sqrt to multiply times top and bottom to get rid of the sqrt on the bottom.
In this case the magic number works like this (a-b)*(a+b)=a^2-b^2. When you square a square root it stops being a square root.
In most cases there is still a denominator but in this intriguing case the denominator dissapears altogether.
{{{2/(sqrt(6)-sqrt(5))}}}
={{{2/(sqrt(6)-sqrt(5))*(sqrt(6)+sqrt(5))/(sqrt(6)+sqrt(5))}}}
={{{2(sqrt(6)+sqrt(5))/(6-5)}}}
={{{2(sqrt(6)+sqrt(5))}}}
Ed