Question 1189820

{{{2y=2x+6}}}....eq.1
{{{y=2x+4}}}....eq.2
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since in eq.2  {{{y}}} is expressed in terms of {{{x}}}, substitute it in eq.1

{{{2(2x+4)=2x+6}}}....eq.1, solve for {{{x}}}

{{{4x+8=2x+6}}}

{{{4x-2x=6-8}}}

{{{2x=-2}}}

{{{x=-1}}}

go to

{{{y=2x+4}}}....eq.2, substitute {{{x}}}

{{{y=2(-1)+4}}}

{{{y=-2+4}}}

{{{y=2}}}


solution:{{{x=-1}}}, {{{y=2}}}