Question 1189533

Solve in integer numbers 2^(x+1) = 3^y+2 - 3^y.
<pre>If this is {{{matrix(1,3, 2^(x + 1), "=", 3^(y + 2) - 3^y)}}}, then we get: {{{matrix(7,3, (2^x)(2^1), "=", (3^y)(3^2) - 3^y, (2^x)(2^1), "=", (3^y)(3^2 - 1), (2^x)2, "=", (3^y)8, 2^x, "=", (3^y)8/2, 2^x, "=", 4(3^y), 2^x, "=", (2^2)(3^y), 2^(x)(1), "=", (2^2)(3^y))}}}

              {{{system(matrix(1,7, 2^x, "=", 2^2, "---", EQUATING, 1^(st), factors), 
highlight_green(matrix(1,3, x, "=", 2)))}}}        {{{system(matrix(1,7, 1, "=", 3^y, "---", EQUATING, 2^(nd), factors), 
matrix(1,8, 3^o, "=", 3^y, "---", CONVERTING, 1, to, 3^o), 
highlight_green(matrix(1,3, 0, "=", y)))}}} 

               <font color = blue><font size = 4><b>You can do the check!!</font></font></b></pre>