Question 1189715
.
<pre>

The three possible ways to present the number 89 as the sum of three squares are


    89 =  9 + 64 + 16 = 3^2 + 8^2 + 4^2   ( so, (a,b,c) = (3,8,4) ),

    89 = 49 + 36 +  4 = 7^2 + 6^2 + 2^2   ( so, (d,e,f) = (7,6,2) ),

    89 = 81 +  4 +  4 = 9^2 + 2^2 + 2^2   ( so, (g,h,i) = (9,2,2) ).


Then  (a+b+c)*(d+e+f)*(g+h+i) = (3+8+4)*(7+6+2)*(9+2+2) = 15*15*13 = 2925.    <U>ANSWER</U>
</pre>

Solved.