Question 1189692
<font color=black size=3>
Let
A = number of seats in section A
B = number of seats in section B
C = number of seats in section C


The stadium has 48000 seats total
A+B+C = 48000


"The number of seats in Section A equals the total number of seats in Sections B and C."
So,
A = B+C


The previous equation
A+B+C = 48000
updates to
B+C+B+C = 48000
2B+2C = 48000
2(B+C) = 48000
after replacing A with B+C


Let's solve for C
2(B+C) = 48000
B+C = 48000/2
B+C = 24000
C = 24000-B


Now use these two facts
"Seats sell for ​$35 in Section​ A, ​$30 in Section​ B, and ​$25 in Section C. "
"he stadium takes in ​$1510500 "
to form this equation
35A+30B+25C = 1510500


Plug in A = B+C
35A+30B+25C = 1510500
35(B+C)+30B+25C = 1510500
35B+35C+30B+25C = 1510500
65B+60C = 1510500


Now plug in C = 24000-B and solve for B
65B+60C = 1510500
65B+60(24000-B) = 1510500
65B+1440000-60B = 1510500
5B+1440000 = 1510500
5B = 1510500-1440000
5B = 70500
B = 70500/5
B = 14100


We can use this value to find C
C = 24000-B
C = 24000-14100
C = 9900


Now we can find A
A = B+C
A = 14100+9900
A = 24000


===================================================================================================


To summarize
<font color=red>
A = 24000
B = 14100
C = 9900
</font>
which represents the number of seats from sections A, B, and C in that order.


As a check,
35A+30B+25C = 1510500
35*24000+30*14100+25*9900 = 1510500
840000+423000+247500 = 1510500
1510500 = 1510500


Also,
A+B+C = 24000+14100+9900 = 48000
The answer is confirmed.
</font>