Question 1189682
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Drawing
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A = ship's location
B = lighthouse 1
C = lighthouse 2


Angle A = 30 degrees
Angle B = x degrees
Angle C = 180-A-B = 180-30-x = 150-x degrees


Apply the law of sines to find x
sin(A)/a = sin(C)/c 
sin(30)/3 = sin(150-x)/9.8 
0.5/3 = sin(150-x)/9.8 
0.5*9.8 = 3sin(150-x) 
4.9 = 3sin(150-x) 
3*sin(150-x) = 4.9
sin(150-x) = 1.633333 approximately


We run into a problem. Recall that {{{-1 <= sin(x) <= 1}}}, i.e. the outputs of sine are restricted to the interval between -1 and 1. 
So it's impossible to have sin(150-x) be 1.63 as that's larger than 1.


No triangle is possible with those specified side lengths and angle. 
Please contact your teacher for clarification.
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