Question 1189661
The derivative of 

{{{f(x)=1/sqrt(2x-3) }}}

is

{{{(d/dx)(1/sqrt(2x-3) )}}}


={{{(d/dx)(sqrt(2x-3) ^(-1/2))}}}........apply chain rule


={{{-(1/(2(2x-3)^(3/2)))(d/dx)(2x-3)}}}.........{{{(d/dx)(2x-3)=2}}}


={{{-2/(2(2x-3)^(3/2))}}}


={{{-1/(2x-3)^(3/2)}}}


{{{f}}}'{{{(x)=-1/((2x-3)^(3/2))}}}


domain: { {{{x}}} element {{{R}}} : {{{x>3/2}}} }