Question 1189633
probability of 0 errors for this Poisson distribution is e^(-0.5)*0.5^0*0!=0.6065
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for 10 pages is is 0.6065^10=0.0067,
Also can use Poisson of parameter 5 and looks at probability of 0 errors. Just multiply the Poisson parameter by 5 pages, since the Poisson parameter is proportional to the amount of time or chances.
this is e^(-5)*5^0*0!=0.0067