Question 1189602
 an equation in slope-intercept form of the line is:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept


if a line passes through ({{{6}}},{{{ 10}}}) and is {{{parallel}}} to the graph of {{{y=13x−1}}}, we know that a line will have {{{same}}} slope since parallel to given line

so, slope is {{{m=13}}}

substitute slope and point in {{{y=mx+b}}}

{{{10=13*6+b}}}......solve for {{{b}}}

{{{10=78+b}}}

{{{b=10-78}}}

{{{b=-68}}}

and your equation is:


{{{y=13x-68}}}



{{{drawing( 600, 600, -10, 10, -15, 15,
circle(6,10,.12), locate(6,10,p(6,10)),
graph( 600, 600, -10, 10, -15, 15, 13x-1,13x-68)) }}}